python - match a pattern and select specific lines in a file -


i have text file displayed below. select 2 lines (line 1 , line 2) under class 10 block only.

thu may 29 14:16:00 pdt 2014 class 09 line 0 line 1 line 2 -- class 10 line 0 line 1 line 2 -- class 11 line 0 line 1 line 2 -- thu may 29 14:20:00 pdt 2014 class 09 line 0 line 1 line 2 -- class 10 line 0 line 1 line 2 -- class 11 line 0 line 1 line 2 -- 

i have tried following, linecache grabs line 1 only. find way grab line1 first line2. idea? thanks

numoflines = sum(1 line in open('text.txt')) print(num_lines) in range(start,numoflines,step):       linea = linecache.getline('text.txt', i)     print linea 

numoflines = sum(1 line in open('text.txt')) 

this line counts lines in file , that's it. not want.

not sure why you'd want linecache. , don't show how compute start or step, bug is.

what want this:

def reading_function():     searching = true     linestoread = 2     open('text.txt') f:         line in f:             if searching , line.strip() == "class 10":                 searching = false             elif not searching:                 print line.strip()                 linestoread -= 1                 if linestoread == 0:                     return 

Comments

Popular posts from this blog

google api - Incomplete response from Gmail API threads.list -

Installing Android SQLite Asset Helper -

Qt Creator - Searching files with Locator including folder -