Json_encode user input (php code) without eval? -

i want return json_encoded string form input this

<input name="test" value="array(1,2,3)"> 

php should return: [1,2,3]

i can achieve eval doing : eval("\$str=json_encode($test);");

but running eval on user input sounds asking trouble.

any other options?

here approach run php code string without using eval

function fakeeval($phpcode) {    $tmpfname = tempnam("/tmp", "fakeeval");    $handle = fopen($tmpfname, "w+");    fwrite($handle, "<?php\n" . $phpcode);    fclose($handle);    include $tmpfname;    unlink($tmpfname);    return get_defined_vars(); }  extract(fakeeval('$test='. $_post['test'].';')); $json = json_encode($test); 

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