python - BeautifulSoup: How to get the nearest tag -

i have xml file following data

<year>2013</year> <yousavespend>2500</yousavespend> <yourmpgvehicle> <avgmpg>32.261695541</avgmpg> <citypercent>43</citypercent> <highwaypercent>57</highwaypercent> </yourmpgvehicle>  <year>2013</year> <yousavespend>3000</yousavespend> <yourmpgvehicle> <avgmpg>33.383275416</avgmpg> <citypercent>49</citypercent> <highwaypercent>51</highwaypercent> </yourmpgvehicle>  <year>2012</year> <yousavespend>2500</yousavespend> <yourmpgvehicle> <avgmpg>36.210640188</avgmpg> <citypercent>32</citypercent> <highwaypercent>68</highwaypercent> </yourmpgvehicle> 

i want use beautifulsoup return list of avgmpg year 2013? how can that?

my current effort has been:

for item in soupedcaravgmpgpage.findall('year'):     listofyears.append(''.join(item.findall(text=true)))  item in soupedcaravgmpgpage.findall('avgmpg'):     listofavgmpg.append(''.join(item.findall(text=true)))  print listofyears print listofavgmpg;  dictionaryyeartoavgmpg = dict(zip(listofyears, listofavgmpg)); 

but dictionary not accept duplicates :s

since know elements going near each other, can there searching through next_siblings:

from bs4 import beautifulsoup  open('mpg.xml') f:     contents=f.read()  mpgs = beautifulsoup(contents)  def find_nearest_vehicle(elem):     sibling in elem.next_siblings:         if sibling.name == 'yourmpgvehicle':             return sibling  def find_avg_mpg(elem):     child in elem.children:         if child.name == 'avgmpg':             return child  year_2013 = [year year in mpgs.find_all('year')              if year.string == '2013']  avgmpg = [find_avg_mpg(find_nearest_vehicle(elem)).string           elem in year_2013]  print(avgmpg) 

when run on file, get:

$ python3 mpg.py ['32.261695541', '33.383275416']