python - Best way to replace values in a list based on many indexes -

i have list this:

l = [1,2,3,4,5,6,7,8,9,10]  idx = [2,5,7] 

i want replace values in l 0, using indexes idx. do:

for in idx:     l[i] = 0 

this give: l = [1, 2, 0, 4, 5, 0, 7, 0, 9, 10]

is there better, faster, more pythonic way. small example, if have huge lists?

i think fine. write list comprehension, this:

[v if not in idx else 0 i, v in enumerate(l)] 

or change in place iterating on l

for i, v in enumerate(l):     if in idx:         l[i] = 0  

but find harder read, , slower. don't think other solution beat yours significant margin, ignoring cpu caching.